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Chapter 35: Q. 21 (page 1017)

A narrow beam of white light is incident on a sheet of quartz. The beam disperses in the quartz, with red light (l≈400nm)traveling at an angle of 26.3°with respect to the normal and violet light (l≈400nm) traveling at 25.7° . The index of refraction of quartz for red light is 1.45. What is the index of refraction of quartz for violet light?

Short Answer

Expert verified

The index of refraction of quartz for violet light is1.48.

Step by step solution

01

Given Information.

We have given that:

Red light = (l≈700nm),

An angel = 26.3°,

Normal violet light (l≈400nm),

Traveling 25.7°,

Index of refraction 1.45.

We need find the index of refraction of quartz for violet light.

02

Simply.

As we know:

λ1≈700nm

θ1=26.3°

n2=1.45

λ2≈400nm

θ2=25.7°

03

Calculation

We need to find n2by using formula:

n1sinθ1=n2sinθ2

1.00sinθ1=1.45sin26.3°

39.97°=θ1

⇒1.00sin39.97°=n2sin25.7°
0.6423=n20.4336
n2=0.64230.4336

n2=1.48

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