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Chapter 35: Q. 37 (page 1018)

You’ve been asked to build a telescope from a 2.0xmagnifying lens and a 5.0xmagnifying lens.

a. What is the maximum magnification you can achieve?

b. Which lens should be used as the objective? Explain.

c. What will be the length of your telescope?

Short Answer

Expert verified

a. The maximum magnification isMmax=2.5.

b. The lens should be used as the objective isL≤fR=fL.

c. The length of the telescope isL=7.

Step by step solution

01

Part (a) Step 1: Given Information.

We need to find out the maximum magnification to achieve.

02

Part(a) Step 2 : Simplify

Maximum magnification:

Mmax=fobjfobjMmax=52Mmax=2.5.

03

Part (b) Step 1 : Given Information.

We need to find which lens should be used as the objective.

04

Part (b) Step 2: Explanation.

As we know that the distance between eyepiece and objective lenses are lightly less than to their focal length.

L≤fR+fL.

05

Part (c) Step 1 : Given Information.

We need to find the length of the telescope.

06

Part (c) Step 2: Calculation.

Length of telescope is:

L=fR+fLL=5+2L=7.

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Most popular questions from this chapter

A microscope with a tube length of 180 mm achieves a total magnification of 800* with a 40* objective and a 20* eyepiece. The microscope is focused for viewing with a relaxed eye. How far is the sample from the objective lens?

Two light bulbs are 1.0mapart. from, what distance can these light bulbs be marginally resolved by a small telescope with a 4.0-cm-diameterobjective lens? assume that the lens is diffraction limited andλ=600nm.

The resolution of a digital cameras is limited by two factors diffraction by the lens, a limit of any optical system, and the fact that the sensor is divided into discrete pixels. consirer a typical point-and--shoot camera that has a 20-mm-focal-lengthlens and a sensor with 2.5-μm-widepixels.

(a) . First, assume an ideal, diffractionless lens, at a distance of 100m,what is the smallest distance, in cmbetween two point sources of light that the camera can barely resolve? in answering this question, consider what has to happen on the sensor to show two image points rather than one you can use S1=fbecauses>>f.

(b) . You can achieve the pixel-limied resolution of part a only if the diffraction which of each image point no greater than the diffraction width of image point is no greater than 1pixel in diameter. for what lens diameter is the minimum spot size equal to the width of a pixel ? use 600nmfor the wavelength of light.

(c). what is the f-numberof the lens for the diameter you found in part b? your answer is a quite realistic value of the f-numberat which a camera transitions from being pixel limited to being diffraction limited for f-numbersmaller than this (larger-diameter apertures), the resolution is limited by the pixel size and does not change as you change the apertures. for f-numberlarger than this (smaller-diameter apertures). the resolution is limited by diffraction and it gets worse as you "stop down" to smaller apertures.

A magnifier has a magnification of 5x. How far from the lens should an object be held so that its image is seen at the near-point distance of 25cm? Assume that your is immediately behind the lens.

A diffraction-limited lens can focus light to a 10μmdiameter spot on a screen. Do the following actions make the spot diameter larger, make it smaller, or leave it unchanged?

A. Decreasing the wavelength of the light.

B. Decreasing the lens diameter.

C. Decreasing the lens focal length.

D. Decreasing the lens-to-screen distance.
See all solutions

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