Chapter 35: Q. 40 (page 1018)

Mordern microscopes are more likely to use a camera than human viewing. This is accomplished by replacing the eyepiece in figure $35.14$ with a photo-ocular that focuses the image of the objectives to a real image on the sensor of a digital camera. A typical sensor is $22.5 m m$ wide and consists of $5625 4.0 μ m$ wide pixels. suppose a microscopist pairs a $40 X$ objectives with a $2.5 X$ photo-ocular
a. what is the field of view? That is what width on the microscope stage in $m m$ fills the sensor?
b. The photo of a cell is $120 p i x e l s$ in a diameter. what is the cell's actual diameter in $μ m$ ?

Short Answer

Expert verified

a. The field of view is $ω_{1} = 0.225 m m$ .

b. The cell's actual diameter is $d = 4.8 μ m$ .

Step by step solution

Part (a) Step 1: Given information

We have given that:

Magnification of object $m_{o b j} = 40$ ,

width of typical sensor $ω_{s} = 22.5 m m$ and

magnification of photo ocular $M_{α} = 2.5$ .

We need to find the magnification M .

Part (a) Step 2: Simplification

Let us find Magnification M:

$M = m_{o b j} M_{α}$ (substitute values in equation.)

$M = (40) (2.5)$

$M = 100$

Therefore width $ω_{1}$ will be,

$ω_{1} = \frac{ω_{s}}{M}$

substituting the values we get ,

$ω_{1} = 0.225 m m$

Here, $ω_{1}$ is the field of view.

part (b) Step 1: Given Information

We need to find the cell's actual diameter in $μ m .$

part (b) step 2: Simplification

Firstly we have to find width $ω_{2}$ of the photo of the cell:

$ω_{2} = (120 p i x e l) (4.0 μ m / p i x e l) ω_{2} = 480 μ m$

Therefore Diameter is:

$d = \frac{ω_{2}}{M} d = \frac{480 μ m}{100} d = 4.8 μ m .$ (substituting value in the equation.)

Here, $d$ is the cell's actual diameter.

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Short Answer

Step by step solution

Part (a) Step 1: Given information

Part (a) Step 2: Simplification

part (b) Step 1: Given Information

part (b) step 2: Simplification

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Medical Physics

Magnetism

Physical Quantities And Units

Thermodynamics

Fields in Physics

Measurements

Study anywhere. Anytime. Across all devices.