A magnifier has a magnification of 5x. How far from the lens should an object be held so that its image is seen at the near-point distance of 25cm? Assume that your is immediately behind the lens.

Short Answer

Expert verified

5cmfar from the lens should an object be held so that its image is seen at the near-point distance of 25cm.

Step by step solution

01

Given information

we have given that:

m=5

D=25cm

we need to find the distance f.

02

Simplify

Using the formula:

m=Df

From the formula, let us find the value for f.

localid="1648723478061" m=Df (substitute value in the equation.)

localid="1648723490375" m=25f (multiply both sides with f.)

localid="1648736190470" role="math" 5f=f×25f

localid="1648723581802" 5f=25 (Divide both the sides by 5.)

localid="1648736050288" 5×f5=255

localid="1648723617249" f=5cm.

m=Df5-25f5f-f:

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Most popular questions from this chapter

FIGURE CP35.50shows a simple zoom lens in which the magnitudes of both focal lengths are f. If the spacing d<f, the image of the converging lens falls on the right side of the diverging lens. Our procedure of letting the image of the first lens act as the object of the second lens will continue to work in this case if we use a negative object distance for the second lens. This is called a virtual object. Consider an object very far to the left (s)of the converging lens. Define the effective focal length as the distance from the midpoint between the lenses to the final image.

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