Chapter 35: Q.34 (page 1018)

The cornea, a boundary between the air and the aqueous humor, has a $3.0 c m$ focal length when acting alone. What is its radius of curvature?

Short Answer

Expert verified

The radius of curvature is $R = 0.76 c m$

Step by step solution

Given Information.

We have given that:

The focal length is $3.0 c m$ .

We need find out the radius of curvature.

Simplify

By using formula:

$\frac{n_{1}}{s} + \frac{n_{2}}{s^{'}} = \frac{(n_{1} - n_{2})}{R}$

From previous formula, Let us find R:

$\frac{1}{\infty} + \frac{n_{2}}{f} = \frac{n_{2} - n_{1}}{R} R = f (\frac{n_{2} - n_{1}}{n_{2}}) R = 3.0 \times (\frac{1.34 - 1.00}{1.34}) R = 3.0 \times (\frac{0.34}{1.34}) R = 3.0 \times 0.253 R = 0.76 c m$ .

Here, $n_{1}$ and $n_{2}$ is the refractive index of the first and second medium respectively, $f$ is the focal length and $R$ is the radius of curvature.

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The cornea, a boundary between the air and the aqueous humor, has a $3.0 c m$ focal length when acting alone. What is its radius of curvature?

Short Answer

Step by step solution

Given Information.

Simplify

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The cornea, a boundary between the air and the aqueous humor, has a 3.0cmfocal length when acting alone. What is its radius of curvature?

Short Answer

Step by step solution

Given Information.

Simplify

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Modern Physics

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The cornea, a boundary between the air and the aqueous humor, has a $3.0 c m$ focal length when acting alone. What is its radius of curvature?