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Chapter 35: Q.48 (page 1019)

Your task in physics laboratory is to make a microscope from two lenses. one lens has a focal length of 2.0cm,the other objective, and you want the eyepiece to be 16cmfrom the objective.

(a). For viewing with a relaxed eye, how far should the sample be from the objective lens?

(b). What is the magnification of your microscope?

Short Answer

Expert verified

(a). The sample should be 1.066cmapart from the objective lens.

(b). The magnification of your microscope M≈200.

Step by step solution

01

Part(a) Step 1: Given information

We have given that:

The focal length of eye isfe=2.0cm

the focal length of object isfo=1.0cm

and the distance between eyepiece and object is 16cm.

We need to find what is the magnification of your microscope.

02

Part (a) Step 2: Simplification

We use the formula,

1fo=1S+1d

11-116=1S

1516=1S

S=1.066cm.

Here Sis distance of sample from objective lens, f0is the focal length of the object and dis the distance between lens and object.

03

part (b) step 1: Given Information

We need to find the magnification.

04

part (b) step 2: Calculation

For Magnification we can use:

M=dS1+Dfe

M=161.0661+252

M≈200.

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Most popular questions from this chapter

A reflection telescope is build with a 20cmdiameter mirror having a 1.00mfocal length. it is used with a 10Xeyepiece. what are

(a) the magnification and

(b) the f-numberof the telescope?

Once dark adapter, the pupil of your eye is approximately 7mmdiameter. The headlights of an oncoming car are 120cmapart. if the lens of your eye is diffraction-limited, at what distance are the two headlights marginally resolved? assume a wavelength of 600nmand that the index of refraction inside the eye is 1.33

(Your eye is not really good enough to resolve headlight at this distance, due both to aberrations in the lens and to the size of the receptors in your retina, but it comes reasonably close.

The resolution of a digital camera is limited by two factors:

diffraction by the lens, a limit of any optical system, and the fact

that the sensor is divided into discrete pixels. Consider a typical

point-and-shoot camera that has a 20-mm-focal-length lens and

a sensor with 2.5@mm@wide pixels.

a. First,ass ume an ideal, diffractionless lens. At a distance of

100 m, what is the smallest distance, in cm, between two

point sources of light that the camera can barely resolve? In

answering this question, consider what has to happen on the

sensor to show two image points rather than one. You can use

s′ = f because s W f.

b. You can achieve the pixel-limited resolution of part a only if

the diffraction width of each image point is no greater than

1 pixel in diameter. For what lens diameter is the minimum

spot size equal to the width of a pixel? Use 600 nm for the

wavelength of light.

c. What is the f-number of the lens for the diameter you found in

part b? Your answer is a quite realistic value of the f-number

at which a camera transitions from being pixel limited to

being diffraction limited. For f-numbers smaller than this

(larger-diameter apertures), the resolution is limited by the

pixel size and does not change as you change the aperture. For

f-numbers larger than this (smaller-diameter apertures), the

resolution is limited by diffraction, and it gets worse as you

“stop down” to smaller apertures

What is the f-number of a relaxed eye with the pupil fully dilated to 8.0mm? model the eye as a single lens 2.4 cm in front of the retina

The cornea, a boundary between the air and the aqueous humor, has a 3.0cmfocal length when acting alone. What is its radius of curvature?

See all solutions

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