A 200gair-track glider is attached to a spring. The glider is pushed in 10 cm .and released. A student with a stopwatch finds that 10oscillations take 12.0 s . What is the spring constant?

Short Answer

Expert verified

The spring constant of air track glider isk=5.48N/m

Step by step solution

01

Step :1 Given data 

Mass of the glider is 0.200 g .

No of oscillations is 10 .

Time taken is 12.0 s

m=0.2kg

N=10cycles

tN=12s

Required :K

A=10.0cm

02

Step :2  Magnitude  of time period

The amount of time it takes to complete one cycle, also known as periodic time, is given by

T=2πω=2πmk

localid="1650301186748" T=1210=1.2s

ωis the angular frequency. k is force constant and m is mass attached with spring.

1.2=2π.200k1.44=39.4×.2kk=5.47Nm-1

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