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Chapter 15: Q. 23 (page 416)

A spring is hung from the ceiling. When a block is attached to its end, it stretches 2.0cmbefore reaching its new equilibrium length. The block is then pulled down slightly and released. What is the frequency of oscillation?

Short Answer

Expert verified

The frequency of the oscillation isf=3.5Hz.

Step by step solution

01

Given.

Given

  • x=2.0cm=0.02m

  • g=9.8m.s-2

Required f

02

Finding frequency.

Using equilibrium equation of spring

kx=mg⇒(1)

Equation (1)also can be write in form

gx=km⇒(2)

Compare equation (2)by angular frequency equation

ω2=(2πf)2=km⇒(3)

From (2) and (3) get that

ω2=(2πf)2=gx⇒f=12πgx⇒(4)

Substitution in (4) to get that

f=12π9.80.02=3.5Hz

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