Chapter 15: Q. 4 (page 415)

An object in SHM oscillates with a period of $4.0 s$ and an amplitude of $10 c m$ . How long does the object take to move from $x = 0.0 c m$ to $x = 6.0 c m$ ?

Short Answer

Expert verified

To move from $x = 0.0 c m$ to $x = 6.0 c m$ , the total time taken is $0.4 s$ .

Step by step solution

Given Information

Time period, $T = 4 s$ .

The amplitude, $A = 10 c m$ .

:Formula used

Equation of the simple harmonic motion is $x = A \sin ω t$ .

Where, at time $t$ , $x$ is the position, $A$ is the amplitude and $ω$ is the angular frequency.

Calculation

Substitute the values to obtain $t$ .

6 = 10 \sin [\frac{2 π}{T} \times t] \frac{6}{10} = \sin [\frac{2 π}{4} \times t] \sin^{- 1} (0.6) = \frac{π}{2} \times t t = 0.4 s

Final Answer

To move from $x = 0.0 c m$ to $x = 6.0 c m$ , the total time taken is $0.4 s$ .

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An object in SHM oscillates with a period of $4.0 s$ and an amplitude of $10 c m$ . How long does the object take to move from $x = 0.0 c m$ to $x = 6.0 c m$ ?

Short Answer

Step by step solution

Given Information

:Formula used

Calculation

Final Answer

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An object in SHM oscillates with a period of 4.0sand an amplitude of 10cm. How long does the object take to move from x=0.0cm to x=6.0cm?

Short Answer

Step by step solution

Given Information

:Formula used

Calculation

Final Answer

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Mechanics and Materials

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Study anywhere. Anytime. Across all devices.

An object in SHM oscillates with a period of $4.0 s$ and an amplitude of $10 c m$ . How long does the object take to move from $x = 0.0 c m$ to $x = 6.0 c m$ ?