An object in SHM oscillates with a period of 4.0sand an amplitude of 10cm. How long does the object take to move from x=0.0cm to x=6.0cm?

Short Answer

Expert verified

To move from x=0.0cmto x=6.0cm, the total time taken is 0.4s.

Step by step solution

01

Given Information 

Time period, T=4s.

The amplitude,A=10cm.

02

:Formula used 

Equation of the simple harmonic motion is x=Asinωt.

Where, at time t, xis the position, Ais the amplitude andωis the angular frequency.

03

Calculation 

Substitute the values to obtaint.

6=10sin2πT×t610=sin2π4×tsin-10.6=π2×tt=0.4s
04

Final Answer 

To move from x=0.0cmto x=6.0cm, the total time taken is 0.4s.

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