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Chapter 15: Q.9 - Excercises And Problems (page 415)

An object in simple harmonic motion has an amplitude of 4.0cm, a frequency of 2.0Hz,and a phase constant of 2π/3rad.Draw a position graph showing two cycles of the motion.

Short Answer

Expert verified

position graph as follow

Step by step solution

01

Given information

amplitude a=4.0cm

frequency f=2.0Hz

phase constantθ=2π3rad

02

Explanation

The wave equation is in the form

x=acosωt+θ

The angular frequency is in the form

ω=2πf=4πrad/s

The equation now takes the form of substituting the values of angular frequency and phase constant.

x=(4.0cm)cos4πt+2π3

Therefore the position graph shows two cycles of motion are as follows.

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