Chapter 15: Q.9 - Excercises And Problems (page 415)

An object in simple harmonic motion has an amplitude of $4.0 c m$ , a frequency of $2.0 H z,$ and a phase constant of $2 π / 3 r a d .$ Draw a position graph showing two cycles of the motion.

Short Answer

Expert verified

position graph as follow

Step by step solution

Given information

amplitude $a = 4.0 c m$

frequency $f = 2.0 H z$

phase constant $θ = \frac{2 π}{3} r a d$

Explanation

The wave equation is in the form

$x = a \cos (ω t + θ)$

The angular frequency is in the form

$ω = 2 πf = 4 π r a d / s$

The equation now takes the form of substituting the values of angular frequency and phase constant.

$x = (4.0 c m) \cos (4 π t + \frac{2 π}{3})$

Therefore the position graph shows two cycles of motion are as follows.

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An object in simple harmonic motion has an amplitude of $4.0 c m$ , a frequency of $2.0 H z,$ and a phase constant of $2 π / 3 r a d .$ Draw a position graph showing two cycles of the motion.

Short Answer

Step by step solution

Given information

Explanation

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An object in simple harmonic motion has an amplitude of 4.0cm, a frequency of 2.0Hz,and a phase constant of 2π/3rad.Draw a position graph showing two cycles of the motion.

Short Answer

Step by step solution

Given information

Explanation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Modern Physics

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Study anywhere. Anytime. Across all devices.

An object in simple harmonic motion has an amplitude of $4.0 c m$ , a frequency of $2.0 H z,$ and a phase constant of $2 π / 3 r a d .$ Draw a position graph showing two cycles of the motion.