Chapter 26: Q. 10 (page 737)

Figure Q26.10 shows a $3 V$ battery with metal wires attached to each end. What are the potential differences $∆ V_{12} = V_{2} - V_{1}, ∆ V_{23} = V_{3} - V_{2},$ $∆ V_{34} = V_{4} - V_{3}, and ∆ V_{41} = V_{1} - V_{4}$ ?

Short Answer

Expert verified

The required potential differences are :

∆ V_{12} = 0 V ∆ V_{23} = 3 V ∆ V_{34} = 0 V ∆ V_{14} = 3 V

Step by step solution

: Given information and formula used

Given circuit :

Theory used :

Equipotential or isopotential refers to a region in space where every point in it is at the same potential. This usually refers to a scalar potential

Defining ∆V12,∆V23,∆V34 and ∆V41

If no current is flowing, conducting wires are equipotential. The top wire is at the same potential as the battery's top, and the bottom wire is at the same potential as the battery's bottom.

As a result,

$∆ V_{12} = 0 V ∆ V_{23} = 3 V ∆ V_{34} = 0 V ∆ V_{14} = 3 V$ ,

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Figure Q26.10 shows a $3 V$ battery with metal wires attached to each end. What are the potential differences $∆ V_{12} = V_{2} - V_{1}, ∆ V_{23} = V_{3} - V_{2},$ $∆ V_{34} = V_{4} - V_{3}, and ∆ V_{41} = V_{1} - V_{4}$ ?

Short Answer

Step by step solution

: Given information and formula used

Defining ∆V12,∆V23,∆V34 and ∆V41

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Figure Q26.10 shows a 3Vbattery with metal wires attached to each end. What are the potential differences ∆V12=V2-V1,∆V23=V3-V2,∆V34=V4-V3,and∆V41=V1-V4?

Short Answer

Step by step solution

: Given information and formula used

Defining ∆V12,∆V23,∆V34 and ∆V41

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Medical Physics

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Geometrical and Physical Optics

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Study anywhere. Anytime. Across all devices.

Figure Q26.10 shows a $3 V$ battery with metal wires attached to each end. What are the potential differences $∆ V_{12} = V_{2} - V_{1}, ∆ V_{23} = V_{3} - V_{2},$ $∆ V_{34} = V_{4} - V_{3}, and ∆ V_{41} = V_{1} - V_{4}$ ?