Chapter 26: Q. 13 (page 738)

The electric potential in a region of uniform electric field is $- 1000 V$ at $x = - 1.0 m$ and $+ 1000 V at x = + 1.0 m$ . What is $E_{x}$ ?

Short Answer

Expert verified

$E_{x} = - 1000 V / m$

Step by step solution

Given information and theory used

Given :

The electric potential is : $- 1000 V at x = - 1.0 m$ and

$+ 1000 V at x = + 1.0 m .$

Theory used :

The electric field is expressed as a function of potential as :

E (x) = - \frac{d V (x)}{d x}

Calculating Ex

In a given region, the uniform electric field is equal to minus the difference in potential divided by distance.

So,

$E_{x} = - \frac{1000 V - (- 1000 V)}{1 m - (- 1 m)} = - 1000 V / m$ is the result.

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The electric potential in a region of uniform electric field is $- 1000 V$ at $x = - 1.0 m$ and $+ 1000 V at x = + 1.0 m$ . What is $E_{x}$ ?

Short Answer

Step by step solution

Given information and theory used

Calculating Ex

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The electric potential in a region of uniform electric field is-1000V at x=-1.0m and +1000Vatx=+1.0m. What is Ex?

Short Answer

Step by step solution

Given information and theory used

Calculating Ex

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Measurements

Electricity and Magnetism

Dynamics

Medical Physics

Electrostatics

Physical Quantities And Units

Study anywhere. Anytime. Across all devices.

The electric potential in a region of uniform electric field is $- 1000 V$ at $x = - 1.0 m$ and $+ 1000 V at x = + 1.0 m$ . What is $E_{x}$ ?