Chapter 26: Q. 19 (page 738)

How much work does the electric motor of a Van de Graaff generator do to lift a positive ion $(q = e)$ if the potential of the spherical electrode is $1.0 M V$ ?

Short Answer

Expert verified

Work done is $1.60 \times 10^{- 13} J$

Step by step solution

Given information and theory used

Given :

Charge of positive ion : $q = e$

Potential of the spherical electrode : $1.0 M V$

Theory used :

The work is equal to $W = q ∆ V$

Calculating work done

Since we have, $W = q ∆ V$

$\Rightarrow W = 1.6 \cdot 10^{- 19} C \cdot 1.0 \cdot 10^{6} V = 1.60 \times 10^{- 13} J$

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How much work does the electric motor of a Van de Graaff generator do to lift a positive ion $(q = e)$ if the potential of the spherical electrode is $1.0 M V$ ?

Short Answer

Step by step solution

Given information and theory used

Calculating work done

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How much work does the electric motor of a Van de Graaff generator do to lift a positive ion (q=e) if the potential of the spherical electrode is 1.0MV?

Short Answer

Step by step solution

Given information and theory used

Calculating work done

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How much work does the electric motor of a Van de Graaff generator do to lift a positive ion $(q = e)$ if the potential of the spherical electrode is $1.0 M V$ ?