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Chapter 26: Q. 2 (page 736)

Figure Q26.2 shows the electric potential as a function of x. Draw a graph of Exversusxin this same region of space.

Short Answer

Expert verified

The required graph is

Step by step solution

01

Given information and formula used  

Given :

Theory used :

Electric field is the negative slope (“derivative” or “gradient”) of the potential.

E→=−ΔVΔx

Potential energy is related to electric potential by the charge. It only makes sense if you know the sign & magnitude of the test charge you want to use.

02

Drawing a graph of  Ex versus x

Since E→=−ΔVΔx,so the required graph is :

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Most popular questions from this chapter

Figure Q26.7 shows an electric field diagram. Dashed lines 1 and 2 are two surfaces in space, not physical objects.

a. Is the electric potential at point a higher than, lower than, or equal to the electric potential at point b? Explain.

b. Rank in order, from largest to smallest, the magnitudes of the potential differences ∆Vab,∆Vcd,and∆Vef.

c. Is surface 1 an equipotential surface? What about surface 2? Explain why or why not.

Find expressions for the equivalent capacitance of

(a) Nidentical capacitors Cin parallel and

(b) Nidentical capacitors Cin series.

How much charge does a 9.0V battery transfer from the negative to the positive terminal while doing 27J of work?

A nerve cell in its resting state has a membrane potential of -70mV, meaning that the potential inside the cell is 70mV less than the potential outside due to a layer of negative charge on the inner surface of the cell wall and a layer of positive charge on the outer surface. This effectively makes the cell wall a charged capacitor. When the nerve cell fires, sodium ions,Na+, flood through the cell wall to briefly switch the membrane potential to +40mV. Model the central body of a nerve cell-the soma-as a 50μmdiameter sphere with a 7.0-nm-thick cell wall whose dielectric constant is 9.0. Because a cell's diameter is much larger than the wall thickness, it is reasonable to ignore the curvature of the cell and think of it as a parallel-plate capacitor. How many sodium ions enter the cell as it fires?

A capacitor being charged has a current carrying charge to and away from the plates. In the next chapter we will define current to be dQ/dt the rate of charge flow. What is the current to a 10μF capacitor whose voltage is increasing at the rate of 2.0V/s?
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