Chapter 26: Q. 2 (page 737)

What is the potential difference between $y_{i} = - 5 c m$ and $y_{f} = 5 c m$ in the uniform electric field $\vec{E} = (120, 000 \hat{i} - 50, 000 \hat{j}) V / m$ ?

Short Answer

Expert verified

The potential difference is $5 k V$

Step by step solution

Given information and formula used

Given :

$y_{i} = - 5 c m$ ; and $y_{f} = 5 c m$

Uniform electric field : $\vec{E} = (120, 000 \hat{i} - 50, 000 \hat{j}) V / m$

Formula used :

$∆ V = - ∆ y \cdot E_{y}$

Calculating the required the potential difference

We'll assume the $x$ -component of the position is the same for both positions because we don't know anything about it; for example, both positions are measured along the $y$ -axis.

$∆ y = 0.05 - (- 0.05) = 0.1 m$ will be the difference in the $y$ -component.

With this knowledge, the potential difference will be :

$∆ V = - ∆ y \cdot E_{y} = - 0.1 (- 50000) = 5000 V$

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What is the potential difference between $y_{i} = - 5 c m$ and $y_{f} = 5 c m$ in the uniform electric field $\vec{E} = (120, 000 \hat{i} - 50, 000 \hat{j}) V / m$ ?

Short Answer

Step by step solution

Given information and formula used

Calculating the required the potential difference

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What is the potential difference between $y_{i} = - 5 c m$ and $y_{f} = 5 c m$ in the uniform electric field $\vec{E} = (120, 000 \hat{i} - 50, 000 \hat{j}) V / m$ ?