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Chapter 26: Q. 20 (page 738)

Light from the sun allows a solar cell to move electrons from the positive to the negative terminal, doing 2.4×10-19Jof work per electron. What is the emf of this solar cell?

Short Answer

Expert verified

The emf of the solar cell is1.5V

Step by step solution

01

Given information and theory used

Given :

Work per electron : 2.4×10-19J

Theory used :

The work is equal toW=q∆V

02

Calculating the emf of the solar cell 

Writing ∆Vasemf,εin our case, we have :

ε=Wq=2.4×10-191.6×10-19=1.5V

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You need to construct a 100 pF capacitor for a science project. You plan to cut two L * L metal squares and insert small spacers between their corners. The thinnest spacers you have are 0.20 mm thick. What is the proper value of L?

An infinitely long cylinder of radius Rhas linear charge density I. The potential on the surface of the cylinder isV0, and the electric field outside the cylinder is localid="1648568519666" Er=λ/2π∈0r. Find the potential relative to the surface at a point that is distance r from the axis, assuming localid="1648568540457" r>R.

Capacitors C1=10μFand C2=20μFare each charged to 10V, then disconnected from the battery without changing the charge on the capacitor plates. The two capacitors are then connected in parallel, with the positive plate of C1connected to the negative plate of C2and vice versa. Afterward, what are the charge on and the potential difference across each capacitor?

a. Suppose that E→=0→V/mthroughout some region of space. Can you conclude that V=0Vin this region? Explain.

b. Suppose that V=0V throughout some region of space. Can you conclude that E→=0→V/m in this region? Explain.

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