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Chapter 26: Q. 4 (page 736)

Estimate the electric fields E→1and E→2 at points 1 and 2 in Figure Q26.4. Don’t forget thatE→ is a vector.

Short Answer

Expert verified

The electric field remains constant while the potential increases uniformly.

Step by step solution

01

: Given information and formula used   

Given :

Theory used :

Electric Field is given by : E=Vr

02

Estimating E→1 and E→2

(a) As per the figure,

V = 5 volts, r=0.5m

So, E=50.5=10V/m(direction : Leftwards )

(b) As per the figure,

V = 35 volts, r = 3.5m

So, E=353.5=10V/m(direction : Rightwards )

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Most popular questions from this chapter

A typical cell has a membrane potential of -70mV, meaning that the potential inside the cell is 70mV less than the potential outside due to a layer of negative charge on the inner surface of the cell wall and a layer of positive charge on the outer surface. This effectively makes the cell wall a charged capacitor. Because a cell's diameter is much larger than the wall thickness, it is reasonable to ignore the curvature of the cell and think of it as a parallel-plate capacitor. How much energy is stored in the electric field of a 50μmdiameter cell with a 7.0nmthick cell wall whose dielectric constant is 9.0?

The metal spheres are charged to +-300. Draw this figure on your paper, then draw a plausible contour map of the potential, showing and labeling the equipotential surfaces.

Figure EX26.3 is a graph of Ex. What is the potential difference between xi=1.0mand xf=3.0m?

An isolated 5.0μF parallel-plate capacitor has 4.0mC of charge. An external force changes the distance between the electrodes until the capacitance is 2.0μF. How much work is done by the external force?

How much work does the charge escalator do to move 1.0μC of charge from the negative terminal to the positive terminal of a 1.5V battery?
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