Chapter 26: Q. 5 (page 736)

Estimate the electric fields ${\vec{E}}_{1} and {\vec{E}}_{2}$ at points 1 and 2 in Figure Q26.5. Don’t forget that $\vec{E}$ is a vector.

Short Answer

Expert verified

The electric field varies in the direction 1 to 2.

${\vec{E}}_{1} = - 5 V / m {\vec{E}}_{2} = - 20 V / m$

Step by step solution

Given information and formula used

Given :

Theory used :

Electric Field is given by : $E = \frac{V}{r}$

Estimating E→1 and E→2

(a) We can see that the potential difference in $2 m e t r e s is 10 V o l t s$ , hence the field strength at this point will be $5 V / m$ . The formula is as follows:

localid="1650261683495" $\begin{array}{rcl} {\vec{E}}_{1} & = & \frac{- 10 + 0}{2} \\ = & - 5 V / m \end{array}$

(b) We can see that the potential difference in $1 m e t r e is 20 V o l t s$ , hence the field strength at this location will be $20 V / m$ . The formula is as follows:

localid="1650261669941" $\begin{array}{rcl} {\vec{E}}_{2} & = & \frac{- (40 - 20)}{1} \\ = & - 20 V / m \end{array}$

The vector will point to the left in both circumstances, parallel to the $x$ -axis.

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Estimate the electric fields ${\vec{E}}_{1} and {\vec{E}}_{2}$ at points 1 and 2 in Figure Q26.5. Don’t forget that $\vec{E}$ is a vector.

Short Answer

Step by step solution

Given information and formula used

Estimating E→1 and E→2

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Estimate the electric fields E→1andE→2at points 1 and 2 in Figure Q26.5. Don’t forget that E→is a vector.

Short Answer

Step by step solution

Given information and formula used

Estimating E→1 and E→2

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Famous Physicists

Force

Thermodynamics

Oscillations

Dynamics

Electricity

Study anywhere. Anytime. Across all devices.

Estimate the electric fields ${\vec{E}}_{1} and {\vec{E}}_{2}$ at points 1 and 2 in Figure Q26.5. Don’t forget that $\vec{E}$ is a vector.