Chapter 26: Q. 5 (page 736)

Estimate the electric fields ${\vec{E}}_{1} and {\vec{E}}_{2}$ at points 1 and 2 in Figure Q26.5. Don’t forget that $\vec{E}$ is a vector.

Short Answer

Expert verified

The electric field varies in the direction 1 to 2.

${\vec{E}}_{1} = - 5 V / m {\vec{E}}_{2} = - 20 V / m$

Step by step solution

Given information and formula used

Given :

Theory used :

Electric Field is given by : $E = \frac{V}{r}$

Estimating E→1 and E→2

(a) We can see that the potential difference in $2 m e t r e s is 10 V o l t s$ , hence the field strength at this point will be $5 V / m$ . The formula is as follows:

localid="1650261683495" $\begin{array}{rcl} {\vec{E}}_{1} & = & \frac{- 10 + 0}{2} \\ = & - 5 V / m \end{array}$

(b) We can see that the potential difference in $1 m e t r e is 20 V o l t s$ , hence the field strength at this location will be $20 V / m$ . The formula is as follows:

localid="1650261669941" $\begin{array}{rcl} {\vec{E}}_{2} & = & \frac{- (40 - 20)}{1} \\ = & - 20 V / m \end{array}$

The vector will point to the left in both circumstances, parallel to the $x$ -axis.

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Estimate the electric fields ${\vec{E}}_{1} and {\vec{E}}_{2}$ at points 1 and 2 in Figure Q26.5. Don’t forget that $\vec{E}$ is a vector.

Short Answer

Step by step solution

Given information and formula used

Estimating E→1 and E→2

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Estimate the electric fields E→1andE→2at points 1 and 2 in Figure Q26.5. Don’t forget that E→is a vector.

Short Answer

Step by step solution

Given information and formula used

Estimating E→1 and E→2

One App. One Place for Learning.

Most popular questions from this chapter

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Estimate the electric fields ${\vec{E}}_{1} and {\vec{E}}_{2}$ at points 1 and 2 in Figure Q26.5. Don’t forget that $\vec{E}$ is a vector.