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Chapter 26: Q. 6 (page 736)

An electron is released from rest atx=2m in the potential shown in Figure Q26.6. Does it move? If so, to the left or to the right? Explain.

Short Answer

Expert verified

The electron makes a Rightwardmovement.

Step by step solution

01

Given information and formula used    

Given :

Initial position of electron :x=2m

Graph -

Theory used :

Electric fieldis the negative slope (“derivative” or “gradient”) of the potential.

E→=-ΔVΔx

Potential energy is related to electric potential by the charge. It only makes sense if you know the sign & magnitude of the test charge you want to use.

02

Determining the direction of the electron 

The electron makes a Rightwardmovement.

Because the electric field is the inverse of the electric potential's slope, the electric field will be nonzero and pointing to the left at x=2m.

As a result, the electron will experience a net force to the right and accelerate in that direction.

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