At what speed is an electron's de Broglie wavelength (a) 1.0pm, (b) 1.0nm, (c) 1.0μm, and (d)1.0mm ?

Short Answer

Expert verified

(a) v=7.27×108m/s

(b) v=2.77×108m/s

(c) v=7.27×102m/s

(d)v=0.727m/s

Step by step solution

01

Part(a) Step 1: Given Information 

The electron's de Broglie wave length is1.0pm

02

Part(a) Step 2: Calculation

We can start the solution with expression for de-Broglie wavelength

λ=hmvv=hmλv=6.63×10-349.11×10-311×10-12v=7.27×108m/s

This speed is larger than speed of light, so we must calculate relativistic speed:

λ=hpp=γmvhλ=γmvγ=1h1-v2c2hλ1-v2c2=11-v2c2mv2h2λ2=v2m2+h2λ2c2v=hλ·m2+h2λ2c2v=2.77×108m/s

03

Part(b) Step 1: Given Information 

The electron's de Broglie wave length is1.0nm

04

Part(b) Step 2: Calculation 

For λ=1×10-9we have:

λ=hmvv=hmλv=6.63×10-349.11×10-311×10-9v=7.27×105m/s

05

Part(c) Step 1: Given Information 

The electron's de Broglie wave length is1.0μm

06

Part(c) Step 2: Calculation

For λ=1×10-6we have:

v=hmλv=6.63×10-349.11×10-311×10-6v=7.27×102m/s

07

Part(d) Step 1: Given Information 

The electron's de Broglie wave length is1.0mm

08

Part(d) Step 2: Calculation

For λ=1×10-3we have:

v=hmλv=6.63×10-349.11×10-311×10-3v=0.727m/s

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