a. What wavelength photon does a hydrogen atom emit in a 200199transition?

b. What is the difference in the wavelengths emitted in a localid="1650823513478" 1992transition and a 2002transition?

Short Answer

Expert verified

(a) In a transition, wavelength photon a hydrogen atom emit is λ200199=0.362m

(b) The difference in the wave lengths areΔλ=0.368pm

Step by step solution

01

Part (a) Step 1: Given information

The wavelength of hydrogen atom is200199

02

Part (a) Step 2: Finding emission spectrum wavelength

We can start with an expression for the emission spectrum wavelength.

λnm=λ01m21n2λ200199=91.181091199212002(200199transition)λ200199=0.362m

03

Part (b) Step 1: Given information

The given wavelengths are1992and2002

04

Part (b) Step 2: Finding difference between wavelengths

In the same approach, we can figure out 1992transition and 2002transition

localid="1651154009746" λ1992=91.18×10912211992λ2002=91.18×10912212002Δλ=λ1992λ2002(difference between wavelengths)Δλ=91.18×1091221199291.18×10912212002(substitute)Δλ=0.368pm

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