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Chapter 38: Q 8 (page 1113)

An electron and a proton are each accelerated from rest through a potential difference of 100 V. Afterward, which particle has the larger de Broglie wavelength? Explain.

Short Answer

Expert verified

Electron will have a Higher de-broglie wavelength.

Step by step solution

01

Step 1. Given information is :An electron and a proton accelerated from rest through a potential difference of 100 V.

We need to find out the particle having the larger de Broglie wavelength.

02

Step 2. Using the formula of Wavelength and De-Broglie wavelength.

We know that :

ν=2Kmandλ=hmv⇒λ=hm2Km=h2mKAsde-brogliewavelengthisinverselyproportionaltomassoftheparticle,Theparticlewithsmallermasswillhaveahigherwavelength

As the mass of electron is smaller than that of proton, Electron will have a Higher de-broglie wavelength.

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The electrons in a cathode-ray tube are accelerated through a 250Vpotential difference and then shot through a 33-nm-diameter circular aperture. What is the diameter of the bright spot on an electron detector 1.5mbehind the aperture?

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