Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 34: Q. 6 (page 990)

The mirror in FIGURE EX34.6 deflects a horizontal laser beam by 60∘. What is the angle ϕ?

Short Answer

Expert verified

Angle of the laser beam,ϕ=30°

Step by step solution

01

The Law of Reflection

The incident and reflected rays are parallel to the surface and within the same plane.

θi=θr

02

Estimate the values

In FIGURE 34.6, a horizontal beam strikes the mirror and deflects it by 60degrees.

When we are asked to calculate the angle supported the geometry of the figure, we notice that

θi+ϕ=90°⟶θi=90°-ϕ

θr+60°-ϕ=90°⟶θr=90°-60°-ϕ

03

Find the Angle

θi=θr, In keeping with the rule of reflection. so,

90°-ϕ=90°-60°-ϕ

ϕ=60°-ϕ

2ϕ=60°

ϕ=30°

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Some electro-optic materials can change their index of refraction in response to an applied voltage. Suppose a planoconvex lens (flat on one side, a 15.0 cm radius of curvature on the other), made from a material whose normal index of refraction is 1.500, is creating an image of an object that is 50.0 cm from the lens. By how much would the index of refraction need to be increased to move the image 5.0 cm closer to the lens?

Optical engineers need to know the cone of acceptance of an optical fiber. This is the maximum angle that an entering light ray can make with the axis of the fiber if it is to be guided down the fiber. What is the cone of acceptance of an optical fiber for which the index of refraction of the core is 1.55 while that of the cladding is 1.45? You can model the fiber as a cylinder with a flat entrance face.

3. One problem with using optical fibers for communication is that a light ray passing directly down the center of the fiber takes less time to travel from one end to the other than a ray taking a longer, zig-zag path. Thus light rays starting at the same time but traveling in slightly different directions reach the end of the fiber at different times. This problem can be solved by making the refractive index of the glass change gradually from a higher value in the center to a lower value near the edges of the fiber. Explain how this reduces the difference in travel times.

A 1.0-cm-tall object is 75cmin front of a converging lens that has a 30cmfocal length.

a Use ray tracing to find the position and height of the image. To do this accurately, use a ruler or paper with a grid. Determine the image distance and image height by making measurements on your diagram.
bCalculate the image position and height. Compare with your ray-tracing answers in part a.

A 20-cm-tall object is 40cmin front of a converging lens that has a20cm focal length.
a Use ray tracing to find the position and height of the image. To do this accurately, use a ruler or paper with a grid. Determine the image distance and image height by making measurements on your diagram.
bCalculate the image position and height. Compare with your ray-tracing answers in part a.
See all solutions

Recommended explanations on Physics Textbooks

Electric Charge Field and Potential

Read Explanation

Kinematics Physics

Read Explanation

Electromagnetism

Read Explanation

Circular Motion and Gravitation

Read Explanation

Electricity

Read Explanation

Electricity and Magnetism

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free