Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 34: Q. 7 (page 990)

At what angle ϕshould the laser beam in FIGURE EX34.7 be aimed at the mirrored ceiling in order to hit the midpoint of the far wall?

Short Answer

Expert verified

Angle aimed at the mirrored ceiling to the mid of the wall,ϕ=42°

Step by step solution

01

Laser

A laser beam is a single-wavelength stream of concentrated, coherent light.

02

Find the angle

5-x3=x1.5ϕ=tan-11.51.67

5-x=2x

5=3x

x=53 ϕ=42°

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A concave mirror has a 40cmradius of curvature. How far from the mirror must an object be placed to create an upright image three times the height of the object?

An object is 60cmfrom a screen. What are the radii of a symmetric converging plastic lens (i.e., two equally curved surfaces) that will form an image on the screen twice the height of the object?

The glass core of an optical fiber has an index of refraction1.60. The index of refraction of the cladding is1.48. What is the maximum angle a light ray can make with the wall of the core if it is to remain inside the fiber?

A horizontal meter stick is centered at the bottom of a 3.0m-deep, 3.0m-wide pool of water. How long does the meter stick appear to be as you look at it from the edge of the pool?

Shows a light ray that travels from point A to point B. The ray crosses the boundary at position x, making angles θ1and θ2in the two media. Suppose that you did not know Snell’s law.

A. Write an expression for the time t it takes the light ray to travel from A to B. Your expression should be in terms of the distances a, b, and w; the variable x; and the indices of refraction n1 and n2

B. The time depends on x. There’s one value of x for which the light travels from A to B in the shortest possible time. We’ll call it xmin. Write an expression (but don’t try to solve it!) from which xmincould be found.

C. Now, by using the geometry of the figure, derive Snell’s law from your answer to part b.

You’ve proven that Snell’s law is equivalent to the statement that “light traveling between two points follows the path that requires the shortest time.” This interesting way of thinking about refraction is called Fermat’s principle.
See all solutions

Recommended explanations on Physics Textbooks

Space Physics

Read Explanation

Magnetism

Read Explanation

Engineering Physics

Read Explanation

Particle Model of Matter

Read Explanation

Thermodynamics

Read Explanation

Conservation of Energy and Momentum

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free