Chapter 34: Q. 77 (page 994)
A tall object is placed in front of a mirror. A tall upright image is formed behind the mirror, from the object. What is the focal length of the mirror?
Short Answer
The focal length of the mirror is.
Chapter 34: Q. 77 (page 994)
A tall object is placed in front of a mirror. A tall upright image is formed behind the mirror, from the object. What is the focal length of the mirror?
The focal length of the mirror is.
All the tools & learning materials you need for study success - in one app.
Get started for freeParaxial light rays approach a transparent sphere parallel to an optical axis passing through the center of the sphere. The rays come to a focus on the far surface of the sphere. What is the sphere’s index of refraction?
Some electro-optic materials can change their index of refraction in response to an applied voltage. Suppose a planoconvex lens (flat on one side, a 15.0 cm radius of curvature on the other), made from a material whose normal index of refraction is 1.500, is creating an image of an object that is 50.0 cm from the lens. By how much would the index of refraction need to be increased to move the image 5.0 cm closer to the lens?
A fortune teller’s “crystal ball” (actually just glass) is 10 cm in diameter. Her secret ring is placed 6.0 cm from the edge of the ball.
a. An image of the ring appears on the opposite side of the crystal ball. How far is the image from the center of the ball?
b. Draw a ray diagram showing the formation of the image.
c. The crystal ball is removed and a thin lens is placed where the center of the ball had been. If the image is still in the same position, what is the focal length of the lens?
A-cm-thick layer of water stands on a horizontal slab of glass. A light ray in the air is incident on the waterfrom the normal. What is the ray’s direction of travel in the glass?
A -tall object is in front of a convex mirror that has a focal length. Calculate the position and height of the image. State whether the image is in front of or behind the mirror, and whether the image is upright or inverted.
What do you think about this solution?
We value your feedback to improve our textbook solutions.