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Chapter 34: Q.46 (page 992)

A microscope is focused on a black dot. When a 1.00-cm-thick piece of plastic is placed over the dot, the microscope objective has to be raised 0.40cm to bring the dot back into focus. What is the index of refraction of the plastic?

Short Answer

Expert verified

The index of refraction of the plastic is 1.70

Step by step solution

01

Given information

We are given that the thickness of plastic piece is 1.00cm

and the microscope objective has to be raised 0.40cm to bring the dot back into focus. We have to find refractive index of plastic.

02

Simplify

As we know,

s'=-n2n1s

Where,

n1=refractive index of medium of object

n2=refractive index of medium of observer

s=distance of object

s'=distance of image

Now, according to question

The distance of black dot of plastic piece (object) is s=1.00cm

The distance of image is s'=1.00cm-0.40cm=0.60cm

Refractive index of air is nair=1

nplastic=ss'nairnplastic=1.000.601.00nplastic=1.70

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