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Chapter 36: Q. 31 (page 1060)

A laboratory experiment shoots an electron to the left at 0.90c. What is the electron’s speed, as a fraction of c, relative to a proton moving to the right at 0.90c?

Short Answer

Expert verified

The electron's speed is 0.994c.

Step by step solution

01

Given Information

We have given that a laboratory experiment shoots an electron to the left at 0.90c.

We have to find the electron’s speed, as a fraction of c, relative to a proton moving to the right at 0.90c.

02

Simplify

Frame of Earth : S

Frame of Proton :S'

Smoves atv=0.9c. In the laboratory frame, the electron's velocity is -0.9c.

Using, the Lorentz velocity transformation equation,

u'=u-v1-uvc2u'=-0.9c-0.9c1-(-0.9c)(0.9c)c2u'=-0.994c.

Therefore the electron's speed is 0.994c.

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