At what speed, as a fraction of c, is a particle’s kinetic energy twice its rest energy?

Short Answer

Expert verified

The speed of particle is 0.943c.

Step by step solution

01

Given information

We have given that particle’s kinetic energy twice its rest energy.

02

Step 1. 

The formula of total energy is E=Υpmc2.

Here, m = mass of particle

c = speed of light

Υp= Lorentz factor

We know that total energy is the sum of rest mass energy and kinetic energy.

E=E0+K

Here, E0=rest mass energy

K = kinetic energy

Substituting both values of total energy in formula :

Υpmc2=E0+K

03

Step 2.

We have given that kinetic energy is twice of rest mass energy.

Substituting value in formula :

Υpmc2=E0+2E0

We know that E0=mc2

Substituting the value of E0in formula :

Υpmc2=3mc2

Υp=3m

We know that Υp=11-v2c2

Substituting the value of Υpin formula :

11-v2c2=3

1-v2c2=19

v=83c

v=0.943c

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