At what speed, as a fraction of c, is a particle’s total energy twice its rest energy?

Short Answer

Expert verified

v=32c

Step by step solution

01

Given Information

We have to find the speed, as a fraction of c, is a particle’s total energy twice its rest energy?

02

Simplify

Total energy formula is

Eο=mc21-v2c2

The rest of energy formula is

E=mc2

Now we will find the total energy twice its rest energy.

Eο=2Emc21-v2c2=2mc2mc2=1-v2c2·2mc2c22c2=1-v2c212=1-v2c214=1-v2c24v2=3c2v2=34c2v=32c

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