FIGURE Q17.1 shows a standing wave oscillating on a string at frequency f0. a. What mode (m-value) is this? b. How many antinodes will there be if the frequency is doubled to 2f0?

Short Answer

Expert verified

a) m = 4, This is a 4 modes wave.

b) There will be 8 antinodes if frequency is doubled.

Step by step solution

01

Part a) Definition of modes

The number of allowed standing waves in a system are called modes of that system.

02

Count the antinodes

We can observe from the figure that there are 4 antinodes in the string. Hence the m value is 4

03

Part b) Doubling the frequency.

If we double the frequency of the wave, it's antinodes will also be doubled.

So therefore we will end up with 4 x 2 = 8 antinodes.

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