FIGURE EX17.28 shows the circular wave fronts emitted by two

wave sources.

a. Are these sources in phase or out of phase? Explain.

b. Make a table with rows labeled P, Q, and R and columns

labeled $r_1,r_2,∆r,$and C/D. Fill in the table for points P, Q,

and R, giving the distances as multiples of l and indicating,

with a C or a D, whether the interference at that point is

constructive or destructive.

When two wavefronts travel equidistance from the source which means the wavefronts travels same distance in a period of time, then the wavefronts are said to be in phase.

When two waves are said to be moving out of phase, they are not equidistant from the source.

The wave fronts of each source have not moved the same distance from their sources. Thus, the circular wave fronts emitted by the two sources indicate the sources are out of phase.

• According to the given diagram, the wavefront labelled as 1 has moved a wavelength of $\lambda$and the wavefront 2 moved a wavelength of $\frac{\lambda }{2}$. So, for a wavelength difference of $\frac{\lambda }{2}$, the phase change is localid="1650366238074" ${\varphi }_o=\pi$.
• At point P, the wavefront 1 moves a distance of localid="1650366518004" $r_1=2\lambda$and wavefront 2 moves a distance of localid="1650366532961" $r_2=3\lambda$. Therefore, the phase difference of the two waves at the point is,

localid="1650372602103" $$\begin{gathered} ∆\varphi =\frac{2\pi ∆r}{\lambda }+{\varphi }_o \\ ∆\varphi =\frac{2\pi \left(3\lambda -2\lambda \right)}{\lambda }+{\varphi }_o \\ ∆\varphi =2\pi +\pi \\ ∆\varphi =3\pi \end{gathered}$$

This corresponds to destructive interference.

• At point Q, the wavefront 1 moves a distance of localid="1650366699707" $r_1=3\lambda$and wavefront 2 moves a distance of localid="1650366650967" $r_2=\frac{3\lambda }{2}$. Therefore, the phase difference of the two waves at the point is,

localid="1650372753433" $$\begin{gathered} ∆\varphi =\frac{2\pi ∆r}{\lambda }+{\varphi }_o \\ ∆\varphi =\frac{2\pi \left(3\lambda -{\displaystyle \frac{3\lambda }{2}}\right)}{\lambda }+{\varphi }_o \\ ∆\varphi =\frac{\left(2\pi \times \frac{3\lambda }{2}\right)}{\lambda }+\pi \\ ∆\varphi =3\pi +\pi \\ ∆\varphi =4\pi \end{gathered}$$

This corresponds to constructive interference.

• At point R, the wavefront 1 moves a distance of $r_1=\frac{5}{2}\lambda$and wavefront 2 moves a distance of $r_2=3\lambda$. Therefore, the phase difference of the two waves at the point is,

$$\begin{gathered} ∆\varphi =\frac{2\pi ∆r}{\lambda }+{\varphi }_o \\ ∆\varphi =\frac{2\pi \left(3\lambda -{\displaystyle \frac{5\lambda }{2}}\right)}{\lambda }+{\varphi }_o \\ ∆\varphi =\frac{\left(2\pi \times {\displaystyle \frac{\lambda }{2}}\right)}{\lambda }+\pi \\ ∆\varphi =\pi +\pi \\ ∆\varphi =2\pi \end{gathered}$$

This corresponds to constructive interference.

If we mention the details of the interference in a table, it should be like: