Two in-phase loudspeakers, which emit sound in all directions,

are sitting side by side. One of them is moved sideways by 3.0 m, then forward by 4.0 m. Afterward, constructive interference is

observed 14and 34of the distance between the speakers along the line that joins them. What is the maximum possible wavelength of the sound waves?

Short Answer

Expert verified

The maximum possible wavelength of the sound waves is5m.

Step by step solution

01

Given data

Out of two loudspeakers, of them is moved sideways by 3.0 m and then forward by 4.0 m.

A constructive interference is observed 14and 34of the distance between the speakers along the line that joins them.

Therefore, the position of the loudspeakers should be as follows:

02

Determination of the maximum possible wavelength

The final distance between the speakers can be obtained by applying the Pythagorean theorem as,

d=32+42md=25md=5m

Therefore, the position of the loudspeaker should be as given below:

Now, the distance between the two spots producing constructive interference is,

D=345m-145mD=52m

As the constructive interference happens when the distance between the two spots is, D=λ2

Thus, the longest wavelength possible in this situation must beλ2=52mλ=5m

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Most popular questions from this chapter

Two in-phase speakers 2.0 m apart in a plane are emitting 1800 Hz sound waves into a room where the speed of sound is 340 m/s. Is the point 4.0 m in front of one of the speakers, perpendicular to the plane of the speakers, a point of maximum constructive interference, maximum destructive interference, or something in between?

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