When mass Mis tied to the bottom of a long, thin wire suspended from the ceiling, the wire's second-harmonic frequency is200HzAdding an additional1.0kgto the hanging mass increases the second-harmonic frequency245Hz. What is M?

Short Answer

Expert verified

The suspended mass is 2kg.

Step by step solution

01

Given information

Second harmonic frequency when massMis suspendedf=200Hz.

When is suspended, f'=245Hz(second harmonic frequency)

Length of wire L=(same for both frequencies as the same wire is used for both masses)μ=(Same for both frequencies as the same wire is used)

Formula:

f=1LTμ..

(General frequency for the second harmonic)

T=Massxgravity.........................

(Tension in the wire due to suspended masses)

02

Calculation

(I) When the mass 'M'is suspended

f=1LTμ200=1LMgμ

Both sides are squaring up

40000=1L2MRμ

(II) when the mass 'M+1'is suspended.

f'=1LTμ

245=1L(M+I)μ

Both sides are squaring up

60025=1L2(M+1)gμ

Dividing equation (I) from equation (II)

We compute that the initial mass hanging from the wire is 2kg using both frequencies.

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