Two circular disks spaced0.50mmapart form a parallel-plate capacitor. Transferring3.0×109electrons from one disk to the other causes the electric field strength to be2.0×105N/C. What are the diameters of the disks?

Short Answer

Expert verified

Diameter of disk is1.85cm.

Step by step solution

01

Formula for area and Electric field intensity

Electric field between capacitor is2×105N/C

Charge is3×109charge of electron.

Q=3×109×1.6×10-19C

Area of circle of radiusris,

A=πr2........1

Electric field due to parallel plate capacitor is,

E=QϵoA............2

02

Calculation for radius of disk

Substitute equation1in equation2then value ofris given by,

E=Qϵoπr2

r2=QϵOπE

r=QϵoπE

=3×109×1.6×10-19Cπ8.85×10-12C2/N·m22×105N/C

r=9.29×10-3m

03

Calculation for diameter of disk

Substitute r=9.29×10-3min below formula,

D=2r

D=2×(9.29×10-3)

D=1.85cm

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Most popular questions from this chapter

FIGURE shows a thin rod of length Lwith total charge Q.

a. Find an expression for the electric field strength at point Pon the axis of the rod at distance rfrom the center.

b. Verify that your expression has the expected behavior if rL.

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