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Chapter 25: Q. 10 (page 708)

FIGUREQ25.10 shows two points near a positive point charge.
aWhat is the ratioV2V1 of the electric potentials? Explain.
bWhat is the ratio E2E1of the electric field strengths?

Short Answer

Expert verified

aThe ratio of electric potentials is V2/V1=1/3.

bThe ratio of electric field strength is E2/E1=1/9.

Step by step solution

01

Step: 1 Electric potential:

Electrical capacitance is measured in Farads and is defined as the ratio of charge to potential difference. The ratio of the electromotive force on each conductor to the voltage differential between them is known as capacitance.

02

Step: 2 Ratio of electric potentials: (part a)

Charge qis same.

V=q4πϵ0r

role="math" localid="1648811378097" V2/V1=r1/r2V2/V1=1/3.
03

Step: 3 Ratio of electric field strength: (part b)

The charge qis contant,

E=q4πϵ0r2E2/E1=r12/r22E2/E1=1/9.

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