An electron with an initial speed of 500,000m/sis brought to rest by an electric field.

a. Did the electron move into a region of higher potential or lower potential?

b. What was the potential difference that stopped the electron?

Short Answer

Expert verified

a. The electron has shifted into a lower-potential zone.

b.V12=0.712V

Step by step solution

01

Given information and theory used 

Given : Electron's initial speed : 500,000m/s

Theory used :

From the equation ofconservation of energy, we have :mv22=-eV12

02

Determining if the proton moves into a region of higher potential or lower potential  

a. Because the kinetic energy of the system has reduced, the potential energy has increased. The product of the charge and the potential difference equals the change in potential energy. Because the electron is negatively charged, the potential energy must increase in order for the potential energy to grow.

As a result, the electron has shifted into a lower-potential zone.

03

Determining the potential difference that stopped the proton  

b. As a result of energy conservation we have :

mv22=-eV12V12=-mv22e

Substituting m=9.11×10-31kg,e=1.60×10-19C, we have :

V12=0.712V

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