Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 25: Q. 17 (page 709)

Through what potential difference must a proton be accelerated to reach the speed it would have by falling 100min vacuum?

Short Answer

Expert verified

The potential difference by which the proton is to be accelerated is∆V=1.02×10-5volts

Step by step solution

01

Given information and theory used 

Given : Proton falls : 100min vacuum

Theory used :

From the equation of conservation of energy, we have :mgh=q∆V

02

calculating the potential difference by which the proton is to be accelerated.

A proton will have an energy of mghif it falls in vacuum from a height of h

Rewriting rule of conservation of energy we have :

∆V=mghq

In terms of numbers, we have

∆V=1.67×10-27×9.81×1001.6×10-19=1.02×10-5volts

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

FIGUREQ25.2shows the potential energy of a proton q=+eand a lead nucleusq=+82e. The horizontal scale is in units of femtometers, where 1fm=10-15m.

aA proton is fired toward a lead nucleus from very far away. How much initial kinetic energy does the proton need to reach a turning point10fm from the nucleus? Explain.
bHow much kinetic energy does the proton of part a have when it is20fmfrom the nucleus and moving toward it, before the collision?

A Van de Graaff generator is a device for generating a large electric potential by building up charge on a hollow metal sphere. A typical classroom-demonstration model has a diameter of 30cm.

a. How much charge is needed on the sphere for its potential to be500,000V?

b. What is the electric field strength just outside the surface of the sphere when it is charged to 500,000V?

A water molecule perpendicular to an electric field has 1.0×10-21J more potential energy than a water molecule aligned with the field. The dipole moment of a water molecule is 6.2×10-30Cm. What is the strength of the electric field?

A proton is fired from far away toward the nucleus of an iron atom. Iron is element number 26, and the diameter of the nucleus is 9.0fm. What initial speed does the proton need to just reach the surface of the nucleus? Assume the nucleus remains at rest.

The wire in FIGURE P25.73 has linear charge density λ. What is the electric potential at the center of the semicircle?
See all solutions

Recommended explanations on Physics Textbooks

Measurements

Read Explanation

Dynamics

Read Explanation

Solid State Physics

Read Explanation

Electricity and Magnetism

Read Explanation

Force

Read Explanation

Physics of Motion

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free