Chapter 25: Q. 17 (page 709)

Through what potential difference must a proton be accelerated to reach the speed it would have by falling $100 m$ in vacuum?

Short Answer

Expert verified

The potential difference by which the proton is to be accelerated is $∆ V = 1.02 \times 10^{- 5} v o l t s$

Step by step solution

Given information and theory used

Given : Proton falls : $100 m$ in vacuum

Theory used :

From the equation of conservation of energy, we have : $m g h = q ∆ V$

calculating the potential difference by which the proton is to be accelerated.

A proton will have an energy of $m g h$ if it falls in vacuum from a height of $h$

Rewriting rule of conservation of energy we have :

$∆ V = \frac{m g h}{q}$

In terms of numbers, we have

$∆ V = \frac{1.67 \times 10^{- 27} \times 9.81 \times 100}{1.6 \times 10^{- 19}} = 1.02 \times 10^{- 5} v o l t s$

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Through what potential difference must a proton be accelerated to reach the speed it would have by falling $100 m$ in vacuum?

Short Answer

Step by step solution

Given information and theory used

calculating the potential difference by which the proton is to be accelerated.

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Through what potential difference must a proton be accelerated to reach the speed it would have by falling 100min vacuum?

Short Answer

Step by step solution

Given information and theory used

calculating the potential difference by which the proton is to be accelerated.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Rotational Dynamics

Famous Physicists

Kinematics Physics

Quantum Physics

Measurements

Physics of Motion

Study anywhere. Anytime. Across all devices.

Through what potential difference must a proton be accelerated to reach the speed it would have by falling $100 m$ in vacuum?