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Chapter 25: Q. 71 (page 713)

FIGURE P25.71 shows a thin rod with charge Q that has been bent into a semicircle of radius R. Find an expression for the electric potential at the center.

Short Answer

Expert verified

The electric potential as the center iskQR.

Step by step solution

01

Given Information

We need to find an expression for the electric potential at the center.

02

Explanation

Let us consider that if we have more than one point, the potential can be written as

V=k∑qr.

In this case, one might first thing we need to integrate, but in fact we can't, as all the charge parts, however we split them, are equally distant from the point of interest. That is, we have

V=kR∑qV=kQR

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Most popular questions from this chapter

What is the electric potential energy of the group of charges in FIGURE EX25.6?

Two 2.0-cm-diameter disks spaced 2.0 mm apart form a

parallel-plate capacitor. The electric field between the disks is

5.0×105V/m.

a. What is the voltage across the capacitor?

b. An electron is launched from the negative plate. It strikes the

positive plate at a speed of 2.0×107m/s.

What was the electron’s speed as it left the negative plate?

Show that 1V/m=1N/C.

The electric potential at the dot in FIGURE EX25.32 is 3140VWhat is charge q?

FIGURE P25.69 shows a thin rod of length L and charge Q. Find an expression for the electric potential a distance z away from the center of rod on the line that bisects the rod.'
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