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Chapter 25: Q. 71 (page 713)

FIGURE P25.71 shows a thin rod with charge Q that has been bent into a semicircle of radius R. Find an expression for the electric potential at the center.

Short Answer

Expert verified

The electric potential as the center iskQR.

Step by step solution

01

Given Information

We need to find an expression for the electric potential at the center.

02

Explanation

Let us consider that if we have more than one point, the potential can be written as

V=k∑qr.

In this case, one might first thing we need to integrate, but in fact we can't, as all the charge parts, however we split them, are equally distant from the point of interest. That is, we have

V=kR∑qV=kQR

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Most popular questions from this chapter

A proton is fired from far away toward the nucleus of a mercury atom. Mercury is element number 80, and the diameter of the nucleus is14.0fm . If the proton is fired at a speed of4.0×107m/s, what is its closest approach to the surface of the nucleus? Assume the nucleus remains at rest

A room with 3.0-m-high ceilings has a metal plate on the floor with V = 0 V and a separate metal plate on the ceiling. A 1.0 g glass ball charged to +4.9 nC is shot straight up at 5.0 m/s. How high does the ball go if the ceiling voltage is (a) +3.0×106Vand (b) -3.0×106V?

FIGURE P25.66 shows two uniformly charged spheres.

What is the potential difference between pointsaandb?

Which point is at the higher potential?

A water molecule perpendicular to an electric field has 1.0×10-21J more potential energy than a water molecule aligned with the field. The dipole moment of a water molecule is 6.2×10-30Cm. What is the strength of the electric field?

In Problems 74 through 76 you are given the equation(s) used to solve a problem. For each of these,

a. Write a realistic problem for which this is the correct equation(s).

b. Finish the solution of the problem.

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See all solutions

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