Chapter 25: Q. 8 (page 709)

Two positive point charges are $5.0 cm$ apart. If the electric potential energy is $72 μJ$ , what is the magnitude of the force between the two charges?

Short Answer

Expert verified

The force between the two charges has a magnitude of $1.4 \times 10^{- 3} N$ .

Step by step solution

Formula for magnitude of force

Given information:

Distance between two positive charges is $5.0 c m$ .

Electric potential energy is $72 μ J$ .

Find:

The objective is to find magnitude of the force between two charges.

The potential energy is calculated as follows:

$U = \frac{1}{4 {πε}_{0}} \frac{Q_{1} Q_{2}}{r} . . 1$

when the force's magnitude is

$F = \frac{1}{4 {πε}_{0}} \frac{Q_{1} Q_{2}}{r^{2}} . . . . . . . 2$

$Q_{1}$ -Charge of point $1$

$Q_{2}$ -Charge of point $2$

$r$ -Distance

$U$ -Electric potential energy

Calculation for magnitude of force

when the force's magnitude is

$F = \frac{1}{4 {πε}_{0}} \frac{Q_{1} Q_{2}}{r^{2}}$

Equation $2$ divided by equation $1$ ,

we obtain,

$\frac{F}{U} = \frac{\frac{1}{r^{2}}}{\frac{1}{r}} = \frac{1}{r}$

This results in

$F = \frac{1}{r} U$

$= \frac{72 μJ}{5.0 cm}$

localid="1649412963669" $= 1.4 \times 10^{- 3} N$

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Two positive point charges are $5.0 cm$ apart. If the electric potential energy is $72 μJ$ , what is the magnitude of the force between the two charges?

Short Answer

Step by step solution

Formula for magnitude of force

Calculation for magnitude of force

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Two positive point charges are5.0cm apart. If the electric potential energy is72μJ , what is the magnitude of the force between the two charges?

Short Answer

Step by step solution

Formula for magnitude of force

Calculation for magnitude of force

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Wave Optics

Geometrical and Physical Optics

Fundamentals of Physics

Modern Physics

Further Mechanics and Thermal Physics

Conservation of Energy and Momentum

Study anywhere. Anytime. Across all devices.

Two positive point charges are $5.0 cm$ apart. If the electric potential energy is $72 μJ$ , what is the magnitude of the force between the two charges?