A water molecule perpendicular to an electric field has 1.0×10-21J more potential energy than a water molecule aligned with the field. The dipole moment of a water molecule is 6.2×10-30Cm. What is the strength of the electric field?

Short Answer

Expert verified

The electric field's magnitude is1.61×108N/C.

Step by step solution

01

Given Information

Given:

  • The potential energy of a water molecule perpendicular to an electric field is1.0×10-21J higher than that of a water molecule aligned with the field.
  • Dipole moment, P=6.2×10-30C-m
02

Determine the electric field strength

A water molecule aligned with the field has 1.0×10-21Jmore potential energy than a water molecule perpendicular to the field.

Uperpendicular-Uparallel=1×10-21J..(1)

Compute the water molecule's potential energy perpendicular to the electric field.

Uperpendicular=-PEcos90=0

Estimate the water molecule's potential energy when it is aligned with the electric field.

Uparallel=-PE×cos0

Plugging the values in the above equation

Uparallel=-6.2×10-30E×1

Insert the values in the above equation

0--6.2×10-30E×1=1×10-21E=1.61×108N/C

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