The factor γappears in many relativistic expressions. A value γ=1.01implies that relativity changes the Newtonian values by approximately 1%and that relativistic effects can no longer be ignored. At what kinetic energy, in MeV, is γ=1.01for

(a) an electron,

(b) a proton, and

(c) an alpha particle?

Short Answer

Expert verified

(a) The kinetic energy for an electron is Ek=5.12×103eV

(b) The kinetic energy for a proton is Ek==9.39×106eV

(c) The kinetic energy for an alpha particle is Ek=3.73×107eV

Step by step solution

01

Given Information

Kinetic energy according to relativity is given by γmc2-mc2=mc2(γ-1)=0.01mc2
Where c is the velocity of light in vacuum and is equal to .c=3×108

02

Part (a) Step 1 Calculation

For electron, m=9.1×10-31kg. So kinetic energy is,

Ek=0.01×9.1×10-31×3×1082=8.129×10-16J=5.12×103eV

03

Part (b) Step 1 Calculation

Mass of the proton is, m=1.67×10-27kg. So, kinetic energy is,

Ek=0.11.67×10-27×3×1082=1.50×10-12J=9.39×106eV

04

Part (c) Step 1 Calculation

The mass of the alpha particle is, m=6.64×10-27kg. So the kinetic energy is,

Ek=0.01×6.64×10-27×3×1082=5.98×10-12J=3.73×107eV

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