Chapter 37: Q. 32 (page 1083)

The fission process $n + {}^{235}U \to {}^{236}U \to {}^{144}{Ba} + {}^{89}{Kr} + 3 n$ converts $0.185 u$ of mass into the kinetic energy of the fission products. What is the total kinetic energy in $MeV$ ?

Short Answer

Expert verified

We find the kinetic energy to be equal to, $E_{k} = 167 MeV$

Step by step solution

Given Information

The fission process $n + {}^{235}U \to {}^{236}U \to {}^{144}{Ba} + {}^{89}{Kr} + 3 n$ converts $0.185 u$ of mass into the kinetic energy of the fission products.

Calculation

Here the mass is getting converted to kinetic energy hence the kinetic energy will be equal to
$E_{k} = Δ m c^{2} = 0.185 \times 1.6 \times 10^{- 27} \times {(3 \times 10^{8})}^{2} = 2.66 \times 10^{- 11} J = 1.67 \times 10^{- 8} eV = 167 MeV$

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

The fission process $n + {}^{235}U \to {}^{236}U \to {}^{144}{Ba} + {}^{89}{Kr} + 3 n$ converts $0.185 u$ of mass into the kinetic energy of the fission products. What is the total kinetic energy in $MeV$ ?

Short Answer

Step by step solution

Given Information

Calculation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Rotational Dynamics

Fundamentals of Physics

Wave Optics

Turning Points in Physics

Force

Translational Dynamics

Study anywhere. Anytime. Across all devices.

The fission process n+U235→U236→Ba144+Kr89+3n converts 0.185u of mass into the kinetic energy of the fission products. What is the total kinetic energy in MeV ?

Short Answer

Step by step solution

Given Information

Calculation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Rotational Dynamics

Fundamentals of Physics

Wave Optics

Turning Points in Physics

Force

Translational Dynamics

Study anywhere. Anytime. Across all devices.

The fission process $n + {}^{235}U \to {}^{236}U \to {}^{144}{Ba} + {}^{89}{Kr} + 3 n$ converts $0.185 u$ of mass into the kinetic energy of the fission products. What is the total kinetic energy in $MeV$ ?