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Chapter 37: Q. 6 (page 1081)

What temperature, in °C, is a blackbody whose emission spectrum peaks at (a) 300nmand (b) localid="1649698615260" 3.00μm?

Short Answer

Expert verified

Required temperatures are:

(a) T=9393.67°C

(b) T=693.67°C

Step by step solution

01

Part (a): Step 1: Given information

We have been given the wavelength as:

λ=300nm
02

Part (a): Step 2: Calculation

Using Wien's law,

λ(nm)=2.9·106(nm·K)T

Here λis wavelength in nanometers and Tis temperature in Kelvin.

We get the expression for T: T=2.9·106(nm·K)λ(nm)

Substituting λ=300nm,

T=2.9·106(nm·K)300T=9666.67KT=9393.67°C

03

Part (b): Step 1: Given Information

We have been given the wavelength as:

λ=3.00μm

04

Part (b): Step 2: Calculation

Using Wein's Law:

T=2.9·106(nm·K)3000T=966.67KT=693.67°C

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