Chapter 29: Q. 22 (page 831)

The value of the line integral of $\vec{B}$ around the closed path in FIGURE EX29.22 is $3.77 \times 10^{- 5} Tm$ . What is $I_{3 .}$ ?

Short Answer

Expert verified

The current $I_{3} = 7 A .$

Step by step solution

Given information

We have given,

line integral = $3.77 \times 10^{- 5} Tm$

We have to find the current $I_{3 .}$

Simplify

Using ampere's law, for any closed path is given by,

$\oint \vec{B} . \vec{d S} = μ_{0} I$

Where I is a total enclosed current in the magnetic field curve.

then total current will be

$I = I_{1} + I_{2} + I_{3} I = 2 A - 6 A + I_{3} I = - 4 A + I_{3} . . . . . . . . . . . . . . . . . . . . . . . (1)$

since

$\oint \vec{B} . \vec{d S} = μ_{0} I \oint \vec{B} . \vec{d S} = (4 π \times 10^{- 7} T . m / A) I I = \frac{\oint \vec{B} . \vec{d S}}{4 π \times 10^{- 7}} = \frac{3.77 \times 10^{- 5} T . m}{4 \times 3.14 \times 10^{- 7} T . m / A} I = 3 A$

using equation (1),

$I = - 4 A + I_{3} = 3 A I_{3} = 7 A .$

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The value of the line integral of $\vec{B}$ around the closed path in FIGURE EX29.22 is $3.77 \times 10^{- 5} Tm$ . What is $I_{3 .}$ ?

Short Answer

Step by step solution

Given information

Simplify

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The value of the line integral of B→around the closed path in FIGURE EX29.22 is 3.77×10-5Tm. What isI3.?

Short Answer

Step by step solution

Given information

Simplify

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Modern Physics

Radiation

Nuclear Physics

Magnetism

Electricity

Thermodynamics

Study anywhere. Anytime. Across all devices.

The value of the line integral of $\vec{B}$ around the closed path in FIGURE EX29.22 is $3.77 \times 10^{- 5} Tm$ . What is $I_{3 .}$ ?