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Chapter 29: Q. 22 (page 831)

The value of the line integral of B→around the closed path in FIGURE EX29.22 is 3.77×10-5Tm. What isI3.?

Short Answer

Expert verified

The currentI3=7A.

Step by step solution

01

Given information

We have given,

line integral =3.77×10-5Tm

We have to find the currentI3.

02

Simplify

Using ampere's law, for any closed path is given by,

∮B→.dS→=μ0I

Where I is a total enclosed current in the magnetic field curve.

then total current will be

I=I1+I2+I3I=2A-6A+I3I=-4A+I3.......................(1)

since

∮B→.dS→=μ0I∮B→.dS→=(4π×10-7T.m/A)II=∮B→.dS→4π×10-7=3.77×10-5T.m4×3.14×10-7T.m/AI=3A

using equation (1),

I=-4A+I3=3AI3=7A.

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