Chapter 29: Q. 34 (page 832)

The two $10 cm$ long parallel wires in FIGURE EX29.34 are separated by $5.0 mm$ . For what value of the resistor R will the force between the two wires be $5.4 \times 10^{- 5} N$ ?

Short Answer

Expert verified

The value of R is $3 Ω .$

Step by step solution

Given information

We have given,

Length of the wire = $10 cm$

Separation between the wire = $5 mm$

Force = $5.4 \times 10^{- 5} N$

We have to find the resistance R as shown in the figure.

Simplify

We know the force between two parallel current carrying wire is

$F = \frac{μ_{0} I_{1} I_{2}}{2 πd} L$

using ohm's law in the left circuit,

we can write,

I_{1} R_{1} = V_{1} I_{1} = \frac{V_{1}}{R_{1}} = \frac{9 V}{2 Ω} = 4.5 A

Now substitute the all values that is given in this formula.

$F = 5.4 \times 10^{- 5} N = \frac{(4 π \times 10^{- 7}) \times 4.5 A \times I_{2}}{2 π \times 0.005} I_{2} = 3 A$

Now using the ohm law in right loop, we can write,

$R_{2} = \frac{V_{2}}{I_{2}} R_{2} = \frac{9 V}{3 A} = 3 Ω$

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The two $10 cm$ long parallel wires in FIGURE EX29.34 are separated by $5.0 mm$ . For what value of the resistor R will the force between the two wires be $5.4 \times 10^{- 5} N$ ?

Short Answer

Step by step solution

Given information

Simplify

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The two10cmlong parallel wires in FIGURE EX29.34 are separated by 5.0mm. For what value of the resistor R will the force between the two wires be 5.4×10-5N?

Short Answer

Step by step solution

Given information

Simplify

One App. One Place for Learning.

Most popular questions from this chapter

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Study anywhere. Anytime. Across all devices.

The two $10 cm$ long parallel wires in FIGURE EX29.34 are separated by $5.0 mm$ . For what value of the resistor R will the force between the two wires be $5.4 \times 10^{- 5} N$ ?