Chapter 29: Q. 7 (page 830)

What currents are needed to generate the magnetic field strengths of Table 29.1 at a point $1.0 cm$ from a long, straight wire?

Short Answer

Expert verified

The current required $2.5 A, 250 A, (5 to 50) \times 10^{4} A, 5 \times 10^{5} A$ respectively.

Step by step solution

Step 1; Given information

We have given,

Different strength of the magnetic fields at a distance from the wire is $1 cm .$

We have to find the current required for produce the magnetic field.

Simplify

Since the magnetic field due to long wire is given by,

$B = \frac{μ_{0} I}{2 πr}$

Where

$r = 0.01 m μ_{0} = 4 π \times 10^{- 7}$

Then current will be

$I = 5 \times 10^{4} B$

Now for magnetic field of surface of earth, the current need to be

$I = 5 \times 10^{4} \times 5 \times 10^{- 5} I = 2.5 A$

For Refrigerator magnetic field, the current needs

$I = 5 \times 10^{4} \times 5 \times 10^{- 3} I = 250 A$

For laboratory magnet, the current need

$I = 5 \times 10^{3} to 5 \times 10^{4} A$

For superconducting magnet, the current required

$I = 5 \times 10^{4} \times 10 I = 5 \times 10^{5} A$

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What currents are needed to generate the magnetic field strengths of Table 29.1 at a point $1.0 cm$ from a long, straight wire?

Short Answer

Step by step solution

Step 1; Given information

Simplify

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What currents are needed to generate the magnetic field strengths of Table 29.1 at a point1.0cmfrom a long, straight wire?

Short Answer

Step by step solution

Step 1; Given information

Simplify

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Magnetism and Electromagnetic Induction

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Study anywhere. Anytime. Across all devices.

What currents are needed to generate the magnetic field strengths of Table 29.1 at a point $1.0 cm$ from a long, straight wire?