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Chapter 29: Q.08 (page 830)

The element niobium, which is a metal, is a superconductor (i.e., no electrical resistance) at temperatures below 9K. How-ever, the superconductivity is destroyed if the magnetic field at the surface of the metal reaches or exceeds 0.10T. What is the maximum current in a straight, 3.0-mm-diameter superconducting niobium wire?

Short Answer

Expert verified

I=750A

Step by step solution

01

:Given information

.There is the maximum current in a straight, 3.0-mm-diameter superconducting niobium wire.

02

Step 2:Given explanation

A current-carrying wire produces a magnetic field and the Biot-savart law enables us to calculate the magnitude and direction of this magnetic field. at any point where the magnetic field due to the segment∆s→of current- carrying wire is given by equation 29.7

B=μοI2πr

Our target is to find the current I, so we solve equation 1for I to be in form

I=2πBrμο

03

Step 3:Given simplyfying

Where ris the radius of the wire and it is calculated by

r=d2=3mm2=1.5mm

Now, we plug the values for B,rand μοinto equation 2to get the maximum current

I=2πBrμο=2π0.1T1.5×10-3m4π×10-7T·m/A=750A

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Most popular questions from this chapter

A particle of charge qand mass mmoves in the uniform fields role="math" localid="1648977372617" E⇀=E0k^andB⇀=B0k^. At t=0, the particle has velocity role="math" localid="1648977203095" V0⇀=V0i^. What is the particle's speed at a later time t?

The two10cmlong parallel wires in FIGURE EX29.34 are separated by 5.0mm. For what value of the resistor R will the force between the two wires be 5.4×10-5N?

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