If A particle of charge qand mass mmoves in the uniform fields E=E0k^andB=B0k^. At t=0, the particle has velocity v0=v0i^. What is the particle's speed at a later time r ?

Short Answer

Expert verified

The particle's speed at a later timev=vo2+qEotm2

Step by step solution

01

Given Values 

E=Eok^

B=Bok^

v=voi^

t=0

We use the equations,

FE=qE=qEok^

FM=qv×B=qvoBo(j)

In the x-y plane, for circular movement:

02

Equation Solving

FM=qvoBor^FE=qEok^

F=ma

F1z=qEomaz

F1r=qvoBo=maτ=mvo22

F1t=0

03

Final Equation

we findv(t):

v(t)=vor^+0+aztk^

v(t)=voi^+aztk^

v=vo2+azt2 az=qEom

v=vo2+qEotm2

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