A loudspeaker on a tall pole broadcasts sound waves equally in all directions. What is the speaker’s power output if the sound intensity level is 90 dB at a distance of 20 m?

Short Answer

Expert verified

The power output of the speaker is5W.

Step by step solution

01

Given information

The sound intensity level of the loudspeaker is β=90dB.

Distance isr=20m.

02

Power output of the speaker

The sound level intensity of the speaker is given by β=10dBlog10II01.

The intensity of the sound wave is given by I=Pa2

From (1) and (2) we get,

P=IaP=I0×10β10dB×4πr2

Substitute the given values

P=1×10-12×1090dB10dB×4π202P5W

Therefore, the power output of the speaker is5W.

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