Chapter 16: Q. 60 (page 453)

The string in FIGURE P16.60 has linear density $μ$ . Find an expression in terms of M, $μ$ , and $θ$ for the speed of waves on the string.

Short Answer

Expert verified

Speed of the waves on the string is, $v = \sqrt{\frac{M g \sin θ}{μ}}$

Step by step solution

Introduction

The string has a linear density of $μ$

Mass of the block is $M$

If we consider the string has a tension force of $T$ then the speed can be determined by,

role="math" localid="1648892786316" $v = \sqrt{\frac{T}{μ}}$

Determination of the speed

Tension of the string $(T) =$ Weight component directed downward the slope.

Now, component of weight directed downward the slope is,

$T = M g \sin θ$

Thus, the speed of waves on the string is,

$v = \sqrt{\frac{T}{μ}} v = \sqrt{\frac{M g \sin θ}{μ}}$

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The string in FIGURE P16.60 has linear density $μ$ . Find an expression in terms of M, $μ$ , and $θ$ for the speed of waves on the string.

Short Answer

Step by step solution

Introduction

Determination of the speed

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The string in FIGURE P16.60 has linear density μ. Find an expression in terms of M, μ, and θfor the speed of waves on the string.

Short Answer

Step by step solution

Introduction

Determination of the speed

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Electromagnetism

Modern Physics

Fluids

Translational Dynamics

Force

Magnetism and Electromagnetic Induction

Study anywhere. Anytime. Across all devices.

The string in FIGURE P16.60 has linear density $μ$ . Find an expression in terms of M, $μ$ , and $θ$ for the speed of waves on the string.